How to Pass Sql Parameters in SqlServer througn

Sometimes we need to execute storedprocedures in our

if we want to pass any parameters the following things will help..


SqlConnection con =

new SqlConnection("Data Source=SERVER2;Initial Catalog=IC;User ID=sa;Password=123");

SqlCommand cmd = new SqlCommand("sp_Register",con);

cmd.Parameters.AddWithValue("@fname", TextBox1.Text);

cmd.Parameters.AddWithValue("@lname", TextBox2.Text);

cmd.Parameters.AddWithValue("@address", TextBox3.Text);

cmd.Parameters.AddWithValue("@uname", TextBox4.Text);

cmd.Parameters.AddWithValue("@pwd", TextBox5.Text);

cmd.Parameters.AddWithValue("@mail", TextBox6.Text);

SqlDataAdapter da = new SqlDataAdapter(cmd);

DataSet ds = new DataSet();



SqlParameter[] p = new SqlParameter[9];

p[0] = new SqlParameter("@username", TextBox1.Text);

p[1] = new SqlParameter("@firstname", TextBox2.Text);

p[2] = new SqlParameter("@lastName", TextBox3.Text);

p[3] = new SqlParameter("@state", TextBox4.Text);

p[4] = new SqlParameter("@city", TextBox5.Text);

p[5] = new SqlParameter("@location", TextBox6.Text);

p[6] = new SqlParameter("@mobile", TextBox7.Text);

p[7] = new SqlParameter("@zipcode", TextBox8.Text);

p[8] = new SqlParameter("@emailid", TextBox9.Text);


string _sql = "Sp_UserRegistration";

SqlParameter[] Param = new SqlParameter[6];

Param[0] = new SqlParameter("@fname", SqlDbType.VarChar, 200);

Param[0].Value = TextBox1.Text;

Param[1] = new SqlParameter("@lname", SqlDbType.VarChar, 200);

Param[1].Value = TextBox2.Text;

Param[2] = new SqlParameter("@address", SqlDbType.NVarChar);

Param[2].Value = TextBox3.Text;

Param[3] = new SqlParameter("@uname", SqlDbType.NVarChar);

Param[3].Value = TextBox4.Text;

Param[4] = new SqlParameter("@pwd", SqlDbType.NVarChar);

Param[4].Value = TextBox5.Text;

Param[5] = new SqlParameter("@mail", SqlDbType.VarChar, 100);

Param[5].Value = TextBox6.Text;



Leave a Reply

Fill in your details below or click an icon to log in: Logo

You are commenting using your account. Log Out /  Change )

Google photo

You are commenting using your Google account. Log Out /  Change )

Twitter picture

You are commenting using your Twitter account. Log Out /  Change )

Facebook photo

You are commenting using your Facebook account. Log Out /  Change )

Connecting to %s